Question

An electron is released from rest at a distance of 0.600 m from a large insulating sheet of charge that has uniform surface charge density 3.00×10⁻¹² C/m² .

A. How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 6.00×10⁻² m from the sheet?

Answer 1

To calculate the work done on the electron by the electric field of the sheet, we can use the equation: W = qEd, where q is the charge of the electron, E is the electric field, and d is the distance moved by the electron.

Step-by-step explanation:

To calculate the work done on the electron by the electric field of the sheet, we can use the equation: W = qEd, where W is the work done, q is the charge of the electron, E is the electric field, and d is the distance moved by the electron. In this case, the charge of the electron is -1.60 × 10-19 C and the electric field is given by the surface charge density as E = σ/2ε₀, where σ is the surface charge density and ε₀ is the permittivity of free space. Plugging in the given values, we get E = (3.00 × 10-12 C/m²)/(2 * 8.85 × 10-12 C²/Nm²). The distance moved by the electron is 6.00 × 10-2 m. Now we can calculate the work:

W = (-1.60 × 10-19 C)(3.00 × 10-12 C/m²)/(2 * 8.85 × 10-12 C²/Nm²)(6.00 × 10-2 m)

Solving this equation gives us the work done on the electron by the electric field of the sheet.