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The value of the following Boolean expression is 1. (x + y)(T+ z), x = 1, y = 1, z = 0

a-True
b-False

1 Answer

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Final answer:

After substituting the provided values into the Boolean expression (x + y)(T+ z) and considering T as the Boolean constant true, the result is 2, not 1. Therefore, the statement is false.

Step-by-step explanation:

The question provided involves evaluating the value of a given Boolean expression by substituting the given values for x, y, and z. The expression is (x + y)(T+ z), with x, y, and z being equal to 1, 1, and 0, respectively. The question asks whether this expression evaluates to 1.

Firstly, we substitute the values into the expression as follows: (1 + 1)(T + 0). This simplifies to (2)T, since T is typically used to represent the Boolean constant true, which has a numerical equivalent of 1, the expression becomes 2*1, which is equal to 2.

Therefore, the value of the Boolean expression is 2, not 1. The given statement is false.

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