Final answer:
The probability that the first control device taken from a box of 50, which includes 3 defective ones, is 3/50.
Step-by-step explanation:
The hand deals with the likelihood that the first control device out of a box of 50, which contains 3 defective units, is defective. This is a classic example of a probability problem in combinatorics and probability theory within mathematics. To find the probability of the first device being defective, we consider the total number of defective devices and the total number of devices in the box.
To calculate the probability, we use the formula P(event) = number of favorable outcomes / total number of outcomes. In this case, the number of favorable outcomes (defective devices) is 3, and the total number of outcomes (total devices in the box) is 50. Therefore, the probability that the first control device sampled is defective is P(defective) = 3/50.