Question

How many bits is required to represent the following decimal numbers.

a.2 KiloBits
b. 40 MegaBytes
c. 10 GigaBits
d. 32 MegaBytes

Answer 1

The number of bits required for each decimal number are:

a) 2 KiloBits = 2048 bits

b) 40 MegaBytes = 335,544,320 bits

c) 10 GigaBits = 10,000,000,000 bits

d) 32 MegaBytes = 268,435,456 bits

Step-by-step explanation:

To convert between units of data storage, we need to remember the following relationships:

1 byte = 8 bits

1 kilobyte (KB) = 1024 bytes = 8192 bits

1 megabyte (MB) = 1024 KB = 1,048,576 bytes = 8,388,608 bits

1 gigabyte (GB) = 1024 MB = 1,073,741,824 bytes = 8,589,934,592 bits

a) 2 KiloBits:

2 KiloBits = 2 * 1024 bits = 2048 bits.

b) 40 MegaBytes:

40 MegaBytes = 40 * 8,388,608 bits = 335,544,320 bits.

c) 10 GigaBits:

10 GigaBits = 10 * 1,000,000,000 bits = 10,000,000,000 bits.

d) 32 MegaBytes:

32 MegaBytes = 32 * 8,388,608 bits = 268,435,456 bits.