(a) The length of x is, x = 10π mm.
(b) The area of the net cylinder is A = 80π mm².
Given information:
The radius of the sphere is 5 mm.
(a) To find the value of x:
The value of x is described as the circumference of the sphere.
So,
x = 2πr
Here, r = 5 mm.
x = 2π(5)
x = 10π mm.
(b) To find the area of the net cylinder, use the formula described below,
A = 2πr² + hx.
Here, h = 3 mm, and x = 10π.
A = 2π(5)² + (3)(10π)
A = 50π + 30π
A = 80π mm².