Question

Check whether the following equation is quadratic equation:-
x²-4x-x+1=(x-2)³​

Answer 1

`\Large \underline{\tt Solution} :`

`\tt \dashrightarrow x^2 - 4x - x + 1 = (x-2)^3`

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By using identity :

• 
  `\large \underline{\boxed{\bf{(a-b)^3 = a^3 - b^3 -3a^2b + 3ab^2}}}`

`\tt \dashrightarrow x^2 - 5x + 1 = (x)^3 - (2)^3 - 3(x)^2 (2) + 3(x)(2)^2`

`\tt \dashrightarrow x^2 - 5x + 1 = x^3 - 8 - 6x^2 + 3x * 4`

`\tt \dashrightarrow x^2 - 5x + 1 = x^3 - 8 - 6x^2 + 12x`

`\tt \dashrightarrow x^2 - 5x + 1 - x^3 + 8 + 6x^2 - 12x = 0`

`\tt \dashrightarrow - x^3 + 7x^2 - 17x + 9 = 0`

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As, it isn't in form of ax² + bx + c = 0,

Therefore it isn't quadratic equation.

Answer 2

Solve for x by simplifying both sides of the equation, then isolating the variable.

x≈−0.47082385

image of graph

Explanation:

Hope it is helpful...