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Find the distance from (2, −6, 5) to each of the following.

a) The origin
b) The point (1, -2, 4)
c) The plane x + 2y - z = 0
d) The line passing through (3, 1, -1) and (4, -3, 2)

1 Answer

6 votes

Final answer:

The distance from the point (2, -6, 5) to the origin, another point, a plane, and a line are calculated using various formulas specific to the object in 3D space.

Step-by-step explanation:

To find the distance from a point to various objects in three-dimensional space, different formulas are used depending on the object. The distance from the point (2, −6, 5) to other objects can be found as follows:

  • Distance to the origin is found by applying the distance formula for points in 3D space. Since the origin is at (0, 0, 0), the distance is √((2-0)² + (−6-0)² + (5-0)²).
  • Distance to another point, (1, -2, 4), is also found using the distance formula: √((2-1)² + (−6+2)² + (5-4)²).
  • Distance to a plane given by the equation x + 2y - z = 0 is found using the formula: |Ax1 + By1 + Cz1 + D| / √(A² + B² + C²), substituting the point's coordinates into this formula and the coefficients from the plane's equation.
  • Distance to a line passing through (3, 1, -1) and (4, -3, 2) requires finding the equation of the line, then using a formula for the shortest distance from a point to a line in 3D, which is based on vector projections and cross products.

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