Final answer:
The kinetic energy of a vehicle with a mass of 1990 kg traveling at a speed of 28.0 m/s is calculated using KE = (1/2)mv², resulting in 780,160 Joules or 780.16 kilojoules.
Step-by-step explanation:
To determine the kinetic energy of the vehicle, we can use the kinetic energy formula:
KE = (1/2)mv²
where KE is the kinetic energy, m is the mass of the object, and v is the velocity of the object.
Given that the mass of the vehicle (m) is 1990 kg and its speed (v) is 28.0 m/s, we can plug these values into the formula:
KE = (1/2) × 1990 kg × (28.0 m/s)²
KE = 0.5 × 1990 kg × 784 m²/s²
KE = 995 kg × 784 m²/s²
KE = 780,160 Joules (J)
Hence, the kinetic energy of the vehicle travelling at a speed of 28.0 m/s is 780.16 kilojoules (kJ), as 1 Joule is equivalent to 0.001 kilojoules.