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Q9). Which of the following would be most consistent with mammalian cells in culture that are primarily using glycolysis to make ATP and have a ratio of NADH/NAD+ that is higher than normal?

A) Ethanol is being converted back to pyruvate.
B) Lactate dehydrogenase is being inhibited under anaerobic conditions.
C) ADP is being phosphorylated to ATP too quickly.
D) ATP is being depleted rapidly.

User KIIV
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Final answer:

The most consistent scenario with mammalian cells using glycolysis to make ATP with a high NADH/NAD+ ratio is the fast phosphorylation of ADP to ATP during anaerobic conditions. This allows for the continued production of ATP through glycolysis by regenerating NAD+ through the conversion of pyruvate to lactate. The correct answer is therefore: Answer: C) ADP is being phosphorylated to ATP too quickly.

Step-by-step explanation:

The question addresses the scenario where mammalian cells in culture are relying on glycolysis for ATP production and have a high NADH/NAD+ ratio. Among the options provided, the most likely scenario that would correspond to these conditions is that lactate dehydrogenase is active, converting pyruvate to lactate, which regenerates NAD+ from NADH, thus allowing glycolysis to continue.

This process, known as anaerobic respiration or fermentation, helps to maintain ATP production when oxygen is scarce. Given this context, option B) 'Lactate dehydrogenase is being inhibited under anaerobic conditions' is inconsistent with the scenario.

Among the remaining choices, option D) 'ATP is being depleted rapidly' is also unlikely because glycolysis is functioning to produce ATP.

During glycolysis under anaerobic conditions, ADP is phosphorylated to form ATP, and pyruvate is reduced to lactate to regenerate NAD+. This crucial step ensures that glycolysis can continue to produce ATP even with high NADH/NAD+ ratios and limited oxygen availability.

The correct answer is therefore: Answer: C) ADP is being phosphorylated to ATP too quickly.

User Andyrooger
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