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Write the point-slope form of the equation of the line that passes through the points (-8, 2) and (1, -4). Include your work in your final answer. Type your answer in the box provided to submit your solution.

User TimVdG
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1 Answer

4 votes

Answer:


\displaystyle (y - 2) = -(2)/(3)\, (x + 8).

Explanation:

Given two points
(x_0,\, y_0) and
(x_1,\, y_1) on a line in
\mathsf{2D}, the slope of that line would be:


\begin{aligned} m &= (y_1 - y_0)/(x_1 - x_0) \\ &= (-4 - 2)/(1 - (-8)) = -(2)/(3)\end{aligned}.

For a line with slope
m and a point
(x_0,\, y_0), the point-slope equation of that line would be:


y - y_0 = m \, (x - x_0).

It was already found that for this line, slope
\displaystyle m = -(2)/(3). Take
(x_0,\, y_0) = (-8,\, 2). That is:
x_0 = -8 and
y_0 = 2. Find the equation of this line in point-slope form:


\displaystyle (y - \underbrace{2}_(y_0)) = \underbrace{\left(-(2)/(3)\right)}_(m)\, (x - \underbrace{(-8)}_(x_0)).

Equivalently:


\displaystyle (y - 2) = -(2)/(3)\, (x + 8).

User Nsousa
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