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5. Find the standard form equation for the ellipse.

2x² + 3y² - 4x + 12y = 4

Answer choices in the picture.

5. Find the standard form equation for the ellipse. 2x² + 3y² - 4x + 12y = 4 Answer-example-1
User Luke Page
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The standard form equation is: (x + 1)² / 9 + (y - 1/3)² / 16 = 1.

Here's how to find the standard form equation for the ellipse:

1. Complete the square for the x² term:

Move the constant term to the right side: 2x² + 3y² = 4 + 4x - 12y

Divide both sides by 2 to isolate x²: x² = 2 + 2x - 6y

Add (2/2)² to both sides to complete the square: x² + (1)² = 4 + 2x - 6y + (1)²

Rewrite as (x + 1)² = 9

2. Complete the square for the y² term:

Divide both sides by 3 to isolate y²: y² = 4/3 + 4x/3 - 2y/3

Multiply both sides by 3 to get rid of fractions: 3y² = 12 + 4x - 2y

Add (-2/2)² to both sides to complete the square: 3y² + (1)² = 13 + 4x - 2y + (1)²

* Rewrite as 3(y - 1/3)² = 16

3. Combine the completed squares:

Divide both sides by 9 to get the equation in standard form: (x + 1)²/9 + (y - 1/3)²/16 = 1

Therefore, the standard form equation for the ellipse is:

(x + 1)² / 9 + (y - 1/3)² / 16 = 1

User Dermot
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