Question

A 7.9 kg block initially at rest is pulled to the

right along a horizontal, frictionless surface
by a constant, horizontal force of 12.4 N.
Find the speed of the block after it has
moved 3.7 m.
Answer in units of m/s.

Answer 1

`v=3.4081(m)/(s)`

Step-by-step explanation:

`F=ma\\F=12.4N\\m=7.9kg\\a=(12.4N)/(7.9kg)\\a=1.5696(m)/(s^2)`

`v^2=v_0^2+2a\Delta x\\v_0=0(m)/(s)\\a=1.5696(m)/(s^2)\\\Delta x=3.7m\\v^2=(0(m)/(s))^2+2(1.5696(m)/(s^2))(3.7m)\\v^2=11.6152(m^2)/(s^2)\\v=\sqrt(11.6152(m^2)/(s^2))\\v=3.4081(m)/(s)`