The 95% confidence interval does not include the known concentration of 0.82 ppm Cd^2+. Therefore, at the 95% confidence level, the new method gives a result that differs from the known result of the SRM.
1. Calculate the Mean (
):
The mean (
) is calculated as the sum of all values divided by the number of values.
= (0.782 + 0.762 + 0.825 + 0.838 + 0.761) / 5 = 0.7936
2. Calculate the Standard Deviation (s_x):
The standard deviation (sx) is calculated using the formula:
![\( s_x = √([(0.782-0.7936)^2 + (0.762-0.7936)^2 + \ldots + (0.761-0.7936)^2] / 4) \)](https://img.qammunity.org/2024/formulas/chemistry/college/jilcz3qjx61bnc8j80lrrmkj8tn09fw2eb.png)
s_x ≈ 0.030
3. Calculate the 95% Confidence Interval:
Use the t-distribution table to find the t-value for a 95% confidence level with 4 degrees of freedom (n-1).

Assuming a two-tailed test, let's say t_{0.025,4} is 2.776 (hypothetical value).
Calculate the margin of error (ME):


ME ≈ 0.034
Calculate the confidence interval:
Confidence Interval =
± ME
Confidence Interval ≈ 0.7936 ± 0.034
Confidence Interval ≈ (0.7596, 0.8276)
Complete question:
An environmental scientist developed a new analytical method for the determination of cadmium (cd^2+) in mussels. To validate the method, the researcher measured the Cd^2+ concentration in standard reference material (SRM) 2976 that is known to contain 0.82 plusminus 0.16 ppm Cd^2+. Five replicate measurements of the SRM were obtained using the new method, giving values of 0.782, 0.762, 0.825, 0.838, and 0.761 ppm Cd^2+. Calculate the mean (Bar x), standard deviation (s_x), and the 95% confidence interval for this data set. At list of t values can be found in the student's t table. X Bar = s_x = 95% confidence interval = x Bar plusminus Does the new method give a result that differs from the known result of the SRM at the 95% confidence level?