It seems like there might be an oversight in providing an image or specific values to drag onto the locations. However, based on the information you provided about the logarithmic function g()-log(x+3)-2, we can determine the relevant intervals.
The given logarithmic function has a vertical asymptote at x=-3 (since +3 is inside the logarithm) and an x-intercept at (4,0). The function is decreasing over the interval (0.00).
To find the interval where both functions are positive, we need to consider where g(z) > 0 and where the other logarithmic function is positive. Since g() is a logarithmic function with a vertical asymptote at r -3, it is positive when+3> 0, which implies >-3. Additionally, the other logarithmic function is positive when ≥ 0.
Therefore, the interval where both function positive is (0,0).