Question

A 6.25 L sample of gas is collected at 298 K and 2.50 atm. What is the volume of the sample at STP?

A - 12.4 L
B - 13.1 L
C - 14.3 L
D - 15.0 L

Answer 1

The volume of the 6.25 L gas sample at STP is approximately 14.5 L, which is closest to 14.3 L. Here option C is correct.

The question is about calculating the new volume of a gas when changing conditions to Standard Temperature and Pressure (STP). To solve this, we use the combined gas law, where the pressure, volume, and temperature of a gas have the following relationship:

`P_1(V_1)/(T_1) = P_2(V_2)/(T_2)`

We know the initial conditions (
`P_1, V_1, T_1`) and the final conditions at STP (
`P_2` = 1 atm,
`T_2` = 273 K). Using the given initial conditions:

`V_1` = 6.25 L

`T_1` = 298 K

We can plug these values into the combined gas law equation and solve for the final volume (
`V_2`):

`V_2 = ((P_1 * V_1 * T_2))/((T_1 * P_2))`

`V_2` = (2.50 atm * 6.25 L * 273 K) / (298 K * 1 atm)

`V_2` = (4312.5 L*K) / (298 K)

`V_2` ≈ 14.5 L

Therefore, the correct answer is near to Option C - 14.3 L, which is the volume of the gas at STP.