In triangle RST with centroid Q and VQ as 5, RQ is 5/3, and RV is 10/3. The centroid divides medians in a 2:1 ratio, making the segment from the vertex to the centroid one-third and the segment from the centroid to the midpoint two-thirds.
In a triangle, the centroid is a point of concurrency where the medians intersect. The centroid divides each median into segments in a 2:1 ratio. If Q is the centroid in triangle RST and VQ is given as 5, we can use this information to find RQ and RV.
Let's denote RQ as x and RV as 2x. Since Q is the centroid, we know that the segment from the vertex to the centroid is twice the length of the segment from the centroid to the midpoint of the opposite side.
Given that VQ is 5, it represents the shorter segment (the one-third part). Therefore, x = (1/3) * 5 = 5/3.
Now, we can find RV by doubling x. Therefore, RV = 2 * (5/3) = 10/3.
In conclusion, in triangle RST with centroid Q and VQ given as 5, RQ is 5/3 and RV is 10/3.
complete question should be :
In triangle RST, the centroid Q is a point of concurrency where the medians intersect. It is known that the centroid divides each median into segments in a 2:1 ratio. If the length of VQ is given as 5 units, find the lengths of RQ and RV.