Question

How long is the diagonal of the larger size print? A. 10.3 in. B. 11.8 in. C. 17.2 in. D. 23.3 in.

Answer 1

The correct answer is option B. 11.8 in.

To find the length of the diagonal of the larger print, we can use the Pythagorean theorem, which relates the lengths of the sides of a right-angled triangle. The theorem states that for a right triangle with sides of length
`\(a\)`,
`\(b\)`, and hypotenuse
`\(c\)`, the relationship is given by:

`\[c = √(a^2 + b^2)\]`

In this case, the smaller print forms a right-angled triangle with sides 2.5 inches (width) and 4.3 inches (diagonal). Applying the Pythagorean theorem:

`\[c_{\text{small}} = √(2.5^2 + 4.3^2) \approx √(6.25 + 18.49) \approx √(24.74) \approx 4.97 \text{ inches}\]`

Now, for the larger print, the width is given as 10 inches, and we want to find the diagonal. Using the same formula:

`\[c_{\text{large}} = √(10^2 + b^2)\]`

Comparing the two triangles, we can set
`\(c_{\text{small}} = c_{\text{large}}\)` and solve for
`\(b\)`:

`\[4.97 = √(10^2 + b^2)\]`

Solving for
`\(b\)`:

`\[b \approx √(24.74) \approx 4.97 \text{ inches}\]`

So, the length of the diagonal of the larger size print is approximately 11.8 inches.

The question probable maybe:

Davin orders prints of his school picture in two sizes. The smaller size is 2.5 inches wide with a 4.3 inch diagonal. The larger size is 10 inches wide. How long is the diagonal of the larger size print? 10.3 in. 11.8 in. 17.2 in. 23.3 in.