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Please help I know answer A but the others confuse me

Please help I know answer A but the others confuse me-example-1
User Evernoob
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The value of y in each equation is different from the value of y in the solution to the system of equations. This is because the two lines have different slopes and y-intercepts, and the solution point lies on both lines.

i) The value of y in each equation

The value of y in the equation y = 2x + 5 is different from the value of y in the equation y = -x + 8.

This is because the two lines have different slopes and y-intercepts.

The slope of the line y = 2x + 5 is 2, and the y-intercept is 5.

This means that for every 1 unit increase in x, y increases by 2 units.

The y-intercept represents the point where the line crosses the y-axis, which is (0, 5).

The slope of the line y = -x + 8 is -1, and the y-intercept is 8.

This means that for every 1 unit increase in x, y decreases by 1 unit.

The y-intercept represents the point where the line crosses the y-axis, which is (0, 8).

ii) The value of y compared to the solution in part a)

The value of y in each equation is different from the value of y in the solution to the system of equations, which is (2, 5).

In the system of equations, y = 5 for both equations.

This means that the solution point lies on both lines. However, the solution point is not the only point on either line where y = 5.

For example, on the line y = 2x + 5, the point (-1, 3) also has a y-value of 5.