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Find the vertex axis of symmetry x intercepts y intercepts of y=-1/2x2

User Max Xu
by
8.2k points

1 Answer

5 votes

Answer:

f(x) = - 3x^2 + 3x - 2

Explanation:

x of vertex = x of axis of symmetry:

x

=

(

b

2

a

)

=

3

6

=

1

2

y of vertex:

y

=

f

(

1

2

)

=

3

4

+

3

2

2

=

5

4

y intercept: y = -2

x-intercepts -> y = 0

D = b^2 - 4ac = 9 - 24 = - 15 < 0. There are no real roots (no x-intercepts) because D < 0.

Since a < 0, the parabola opens downward. The parabola is completely below the x-axis.

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User Xcopy
by
8.7k points