Question

A 58 kg person jumps from the ground with an initial velocity of 10 m/s, and then comes to rest at the maximum height. What is the maximum height?

Answer 1

Answer: 5 meters

Step-by-step explanation:

Formula: ke=1/2 mv^2

m=58kg

v=10m/s

put the values in the formula

ke= 1/2 x 58 x 10^2

ke=2900J

Formula: Delta PE_g = mgh

h=?

g= 9.8m/s^2

h=ke/mg

h=2900/58x9.8

h=490

change to the nearest decimal

h=500

The maximum height reached by the person is approximately 5 meters above the ground.