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In a class of 24 students, 5 have a brother and 16 have a sister. There are 5 students who do not have any siblings. What is the probability that a student has a brother given that they have a sister?

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Answer:

The probability of a student having a brother given that they have a sister can be calculated using conditional probability.

Let
\(A\) be the event of having a brother, and
\(B\) be the event of having a sister.

From the information provided:

-
\(P(A) = (5)/(24)\) (5 out of 24 students have a brother)

-
\(P(B) = (16)/(24)\) (16 out of 24 students have a sister)

-
\(P(A \cap B)\) = \(P(A)\)(since having a brother and having a sister are independent events, there's no direct information about this overlap)

The conditional probability formula is:
\(P(A|B) = (P(A \cap B))/(P(B))\)

Substituting the known values:


\[P(A|B) =
(P(A))/(P(B)) = ((5)/(24))/((16)/(24)) = (5)/(16)\]

Therefore, the probability that a student has a brother given that they have a sister is
\((5)/(16)\).

Explanation:

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