Question

Question attatched ​

Answer 1

`\sf\\\textsf{Solution:}\\\textsf{Using the Pythagoras Theorem,}\\hypotenuse^2=base^2+height^2\\or,\ (x+4)^2=(x+2)^2+x^2\\or,\ x^2+8x+16=x^2+4x+4+x^2\\or,\ x^2+4x-8x+4-16=0\\or,\ x^2-4x-12=0\\\textsf{This equation is in the form }x^2+ax+b=0.\\\therefore\ a=-4\ and\ b=-12`

Answer 2

x²– 4x – 12 = 0

To get your answer, the pythagorean theorem is used to solve the problem, as shown in the attachment