Question

The function f(x) = 5(2-1) is shown on the coordinate plane.

Select from the drop-down menus to correctly describe the end
behavior of f(x).
As x decreases without bound, the graph of f(x)
Choose...
V
As x increases without bound, the graph off (2)
Choose...
-2 -1
f(x)
5
4
3+
2+
1+
-1+
-2+
-3+
1
2
3
4
5

Answer 1

The function f(x) = 5(2-1) is a constant function with a value of 5 for all x. As x decreases or increases without bound, the graph of f(x) will be a horizontal line at y = 5.

The function f(x) = 5(2-1) is a constant function. The expression 5(2-1) simplifies to 5(1), which is equal to 5. So, the function f(x) = 5 for all values of x.

As x decreases without bound, the graph of f(x) will approach the value 5. This means that the end behavior of f(x) as x decreases without bound is a horizontal line at y = 5.

Similarly, as x increases without bound, the graph of f(x) will also approach the value 5. So, the end behavior of f(x) as x increases without bound is also a horizontal line at y = 5.

The question probable may be:

What is the nature of the function f(x) = 5(2-1)? How does the graph behave as x decreases or increases without bound, and what is the significance of the constant value in the function?