Question

a beam is supported and loaded as shown in (figure 1). assume that l = 0.40, a = 0.16 m , w = 70 n/m , f = 880 n , i=4.30×10−8m4 , c=1.45×10−2m . the material of the beam is aluminum alloy.

Answer 1

The torque of the system about the support at the wall is 8.82 Nm.

Step-by-step explanation:

The torque of a system is calculated by multiplying the force applied and the perpendicular distance from the point of rotation. In this case, the torque of the system about the support at the wall is calculated by multiplying the weight of the beam by the perpendicular distance between the support point and the center of mass of the beam. The torque can be calculated as follows:

Torque = force x distance = m x g x d

where m is the mass of the beam, g is the acceleration due to gravity, and d is the distance between the support point and the center of mass of the beam.

In this problem, the mass of the beam is 2.0 kg, the mass at the end of the beam is 1.0 kg, and the width of the beam is 0.2 m. The center of mass of the beam is located at a distance of 0.3 m from the support point. Using these values, the torque of the system can be calculated as follows:

Torque = (2.0 kg + 1.0 kg) x 9.8 m/s^2 x 0.3 m = 8.82 Nm