Question

6. Solve the system of equations.
x² + y² + x + 25y + 44 = 0
x + 2y + 3 =0

Answer 1

(1, -2) and (7, -5)

Explanation:

x = -2y-3

(-2y-3)^2 + y^2 -2y-3 + 25y + 44 = 0

4y^2 + 9 + 12y + y^2 + 23y + 41 = 0

5y^2 +35y + 50 = 0

y^2 + 7y + 10 = 0

(y+2)(y+5)=0

y= -2

y = -5

x = -2y-3

x= -2(-2)-3

x = 4-3

x = 1

x= -2(-5)-3

x = 10 - 3

x = 7