Question

Determine the number of protons, neutrons and electrons in the following:

65
29x

A. p⁺ = 29 nº = 36 e⁻ = 36
B. p⁺ =29 n° = 36 e⁻ = 29
C. p⁺ = 36 n° =36 e⁻ =29
D. p⁺ =36 n° = 29 e⁻ = 36
E. p⁺ = 29 n° = 29 e⁻ =36

Answer 1

The correct answer is B. p+ =29 n0 = 36 e- = 29, as the number of protons and electrons equals the atomic number (29), and the number of neutrons is calculated by subtracting the atomic number from the mass number (65 - 29 = 36).

Step-by-step explanation:

To determine the number of protons, neutrons, and electrons in the given isotopic notation 6529xA, we need to examine the atomic number and the mass number. The atomic number, which is 29 in this case, represents the number of protons (p+) and also the number of electrons (e−) in a neutral atom. Since the element symbol 'xA' is not specified, let's assume it is a neutral atom with no charge. The mass number is 65, which is the sum of protons and neutrons (n0). To find the number of neutrons, we subtract the number of protons from the mass number.

So, let's calculate:

• Number of protons (p+) = Atomic number = 29
• Number of electrons (e−) = Number of protons (for a neutral atom) = 29
• Number of neutrons (n0) = Mass number - Atomic number = 65 - 29 = 36

Therefore, the correct answer is B. p+ =29 n0 = 36 e− = 29.