Final answer:
The relative rate of effusion of C2H2 to that of CO2 can be calculated using Graham's law. The molar mass of C2H2 is 26 g/mol and the molar mass of CO2 is 44 g/mol. Therefore, the relative rate of effusion of C2H2 to that of CO2 is approximately 1.30.
Step-by-step explanation:
The relative rate of effusion can be calculated using Graham's law, which states that the relative rate of effusion of two gases is inversely proportional to the square root of their molar masses.
In this case, the molar mass of C2H2 is 26 g/mol and the molar mass of CO2 is 44 g/mol.
Therefore, the relative rate of effusion of C2H2 to that of CO2 can be calculated as:
sqrt(44 g/mol) / sqrt(26 g/mol) = sqrt(44/26)
= sqrt(22/13)
≈ 1.30
So, the relative rate of effusion of C2H2 to that of CO2 is approximately 1.30.