Question

A stone is tossed into the air from ground level with an initial velocity of 15 m/sec height in meters at time t seconds is h(t0 = 15t - 4.9t^2. Compute the average velocity of the stone over the given time intervals. a) [1,1.05] b) [1,1.01] c) [1,1.005] d) [1,1.001]

Answer 1

To find the average velocity of the stone over a given time interval, calculate the displacement by subtracting the values of h(t) at the start and end of the interval and divide by the change in time.

Step-by-step explanation:

The given equation for the height of the stone as a function of time is h(t) = 15t - 4.9t^2.

To find the average velocity over a given time interval, you need to find the displacement (change in position) and divide by the change in time.

To find the displacement, you need to find the values of h(t) at the start and end of the time interval and subtract them.

For example, to find the average velocity over the interval [1, 1.05] seconds, you would calculate h(1.05) - h(1).

Finally, divide the displacement by the change in time to find the average velocity.