Question

point charge q1 = -5.00 nc is at the origin and point charge q2 = 3.00nc is on the x -axis at x = 3.00cm . point p is on the y-axis at y = 4.00cm .

Answer 1

To calculate the electric field at point P on the y-axis, we can use Coulomb's Law.

Step-by-step explanation:

To calculate the electric field at point P on the y-axis, we can use Coulomb's Law:

Electric field (E) = k * (q1 / r1^2) + k * (q2 / r2^2)

where k is the Coulomb's constant, q1 and q2 are the charges at the origin and on the x-axis respectively, and r1 and r2 are the distances from point P to the charges. In this case, q1 = -5.00 nC, q2 = 3.00 nC, r1 = 4.00 cm, and r2 = 5.00 cm. Substituting these values into the formula, we get:

E = (9 * 10^9) * (-5.00 * 10^-9 / (0.04)^2) + (9 * 10^9) * (3.00 * 10^-9 / (0.05)^2)

Calculating this expression will give us the electric field at point P.