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At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressure of He would give a solubility of 0.100 M?​

User Nick Zani
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Final answer:

To find the partial pressure that would give a solubility of 0.100 M, we can use Henry's law by rearranging the equation P = C/k.

Step-by-step explanation:

In this question, we can use Henry's law to determine the solubility of a gaseous solute when its pressure changes. Henry's law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. The equation for Henry's law is:

C = kP

where C is the concentration (or solubility) of the gas in the liquid, k is the Henry's law constant, and P is the partial pressure of the gas.

In this case, we are given the solubility of He in water at a particular temperature: 0.080 M when the partial pressure is 1.7 atm.

To find the partial pressure that would give a solubility of 0.100 M, we can rearrange the Henry's law equation:

P = C/k

Substituting the given values, we have:

P = 0.100 M / 0.080 M/atm

= 1.25 atm

Therefore, a partial pressure of 1.25 atm would give a solubility of 0.100 M.

User Tomas Di Domenico
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