Final answer:
The stress in rod (1) is higher than in rod (2).
Step-by-step explanation:
The stress (σ) in a material is defined as the force (F) applied per unit area (A). Mathematically, it can be expressed as σ = F/A. The cross-sectional area (A) of rod (1) is given as 263 mm², and for rod (2), it is 188 mm².
Now, assuming the same applied force on both rods, the stress in rod (1) can be calculated as follows:
Stress in Rod (1) = Force/Area=F/A1
Similarly, the stress in rod (2) is given by:
Stress in Rod (2) Force/Area=F/A2
As the cross-sectional area of rod (1) is larger than that of rod (2), the stress in rod (1) will be higher for the same applied force. This is because stress is inversely proportional to the cross-sectional area.
The stress in rod (1) is higher than in rod (2) due to the larger cross-sectional area of rod (1). This information is crucial for assessing the mechanical behavior and potential failure points of the welded rods under load.