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What is the minute ventilation (L/min) of a 150-lb (68-kg) male who has a tidal volume 425 mL and a respiratory rate of 12?

1) 3.3
2) 5.1
3) 7.4
4) 6.2

User Jon Nagra
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1 Answer

5 votes

Final answer:

The minute ventilation of a 150-lb male with a tidal volume of 425 mL and a respiratory rate of 12 is 5.1 L/min, calculated by multiplying the tidal volume by the respiratory rate. Option 2 is correct.

Step-by-step explanation:

The minute ventilation is calculated by multiplying the tidal volume (the volume of air inhaled in a single, normal breath) by the respiratory rate (the number of breaths per minute). In this case, the tidal volume is 425 mL (or 0.425 liters) and the respiratory rate is 12 breaths per minute. Therefore, the minute ventilation for a 150-lb male with these respiration parameters is:

Minute Ventilation = Tidal Volume x Respiratory Rate

Minute Ventilation = 0.425 L/breath x 12 breaths/min

Minute Ventilation = 5.1 L/min

The correct answer is 5.1 L/min.

User Scorpian
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