Final answer:
The sound intensity at the position of the microphone is 350,000 W/m². The sound energy impinging on the microphone each second is 35 J.
Step-by-step explanation:
(a) To find the sound intensity at the position of the microphone, we can use the formula:
Intensity = Power / Area
Given that the loudspeaker emits 35 W of sound power and the microphone has a 1.0 cm² area, we need to convert the area to square meters:
1.0 cm² = 0.0001 m²
Substituting the values into the formula:
Intensity = 35 W / 0.0001 m²
Intensity = 350,000 W/m²
So, the sound intensity at the position of the microphone is 350,000 W/m².
(b) To calculate the sound energy impinging on the microphone each second, we can use the formula:
Energy = Power x Time
Given that the power of the loudspeaker is 35 W, we need to convert the time to seconds:
1 second = 1 s
Substituting the values into the formula:
Energy = 35 W x 1 s
Energy = 35 J
So, the sound energy impinging on the microphone each second is 35 J.
Complete question:
A concert loudspeaker suspended high above the ground emits 35 W of sound power. A small microphone with a 1.0 cm2 area is 50 m from the speaker. (a) What is the sound intensity at the position of the microphone? (b) How much sound energy impinges on the microphone each second?