Question

4. Solve each system of equations.
4x^2 - x - 67y + 146 = 0
x - y = 2

Answer 1

(7,5) and (10,8)

Explanation:

x = y+2

4(y+2)^2 -(y+2) - 67y + 146 = 0

4(y^2+4+4y) -y - 2 - 67y + 146 = 0

4y^2+16y+16 - 68y + 144 = 0

4y^2 -52y + 160= 0

y^2 - 13y+40 = 0

(y-8)(y-5) = 0

y = 8

y = 5

x = 5+2 = 7

x = 8 + 2 = 10