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At a point in a stressed body, the stresses are x = 1.0MPa, y = 3.0MPa, z = 5.0MPa, xy = 4.0MPa, zx = 6.0MPa, andyz = 8.0MPa. Determine:

a) the resultant stress S,
b)normal stress n and shear stress nt, on a plane whose outward normal makes equal angles with the x, y, z axes [l=m=n],
c)stress invariants and principal stresses,
d)absolute maximum shear stress.

User Camdixon
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1 Answer

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Final answer:

The resultant stress, normal stress, and shear stress on a plane making equal angles with the x, y, z axes can be calculated using the stress tensor matrix. The stress invariants and principal stresses can also be determined, along with the absolute maximum shear stress.

Step-by-step explanation:

To determine the given quantities, we can use the stress tensor matrix.

a) The resultant stress S can be calculated using the formula:

S = sqrt(x^2 + y^2 + z^2 + 2xy + 2xz + 2yz) = sqrt(1^2 + 3^2 + 5^2 + 2(4) + 2(6) + 2(8)) = sqrt(1 + 9 + 25 + 8 + 12 + 16) = sqrt(71) ≈ 8.43MPa

b) To find the normal stress σn and shear stress τnt, we need to calculate the average stress on a plane making equal angles with the x, y, z axes. The average stress is given by:

σavg = (x + y + z) / 3 = (1 + 3 + 5) / 3 = 3MPa

The normal stress σn is equal to the average stress, so σn = σavg = 3MPa. The shear stress τnt can be calculated using the formula:

τnt = sqrt((x - σavg)^2 + (y - σavg)^2 + (z - σavg)^2 + 2(xy - τxy) + 2(xz - τxz) + 2(yz - τyz)) = sqrt((1 - 3)^2 + (3 - 3)^2 + (5 - 3)^2 + 2(4 - 6) + 2(6 - 6) + 2(8 - 8)) = sqrt(4 + 0 + 4 + 2(2) + 2(0) + 2(0)) = sqrt(12) ≈ 3.464MPa

c) The stress invariants can be calculated using the formulas:

I1 = x + y + z = 1 + 3 + 5 = 9MPa

I2 = xy + xz + yz = 4 + 6 + 8 = 18MPa

I3 = xyz + 2τxyz - τyz(x^2 + y^2 + z^2) - σyz(x + y + z) + Στ^2 = 1(2) - 8(1^2 + 3^2 + 5^2) - 3(1 + 3 + 5) + (4^2 + 6^2 + 8^2) = -41MPa

The principal stresses can be determined using the formulas:

λ^3 - I1λ^2 + I2λ - I3 = 0

By solving this cubic equation, we can find the values of λ, which are the principal stresses.

d) The absolute maximum shear stress can be calculated using the formula:

τmax = sqrt(((x - y)/2)^2 + ((y - z)/2)^2 + ((z - x)/2)^2 + τxy^2 + τxz^2 + τyz^2) = sqrt(((1 - 3)/2)^2 + ((3 - 5)/2)^2 + ((5 - 1)/2)^2 + 4^2 + 6^2 + 8^2) = sqrt((-1/2)^2 + (-1/2)^2 + (2/2)^2 + 16 + 36 + 64) = sqrt(1/4 + 1/4 + 1 + 16 + 36 + 64) = sqrt(117.5) ≈ 10.83MPa

User Bjoern Rennhak
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