Final answer:
To obtain 0.34 gram of AgNO₃, we calculate the moles and then divide by the molarity to find the volume in liters. This results in 3.7 mL, which means none of the provided options are correct.
Step-by-step explanation:
The question seeks to determine the volume of 0.54M AgNO₃ solution required to obtain 0.34 gram of solute. This calculation involves finding the number of moles of AgNO₃ using its molar mass and then using the molarity to find the volume. AgNO₃ has a molar mass of approximately 169.87 g/mol, so 0.34 g is 0.34 g / 169.87 g/mol = 0.002 moles of AgNO₃. Given that Molarity (M) equals moles/Liter (mol/L), we can rearrange the formula to solve for volume: V = moles / M. Therefore, the required volume is 0.002 moles / 0.54 mol/L = 0.0037 Liters, which is 3.7 mL. None of the provided options (a, b, c, d) are correct since the calculated volume is not listed amongst them.