Question

Using the information in the following table, calculate the average rate of formation of P₂O₅ between 10.0 and 40.0 s?

Answer 1

The average rate of formation of P₂O₅ between 10.0 and 40.0 s is X.X units per second.

Step-by-step explanation:

To calculate the average rate of formation of P₂O₅ between 10.0 and 40.0 s, we use the formula:

`\[ \text{Average Rate} = \frac{\text{Change in concentration of P₂O₅}}{\text{Change in time}} \]`

First, find the change in concentration by subtracting the initial concentration (at 10.0 s) from the final concentration (at 40.0 s). Next, determine the change in time by subtracting the initial time from the final time. Finally, plug these values into the formula to obtain the average rate.

`\[ \text{Average Rate} = \frac{[\text{P₂O₅}]_{\text{40.0 s}} - [\text{P₂O₅}]_{\text{10.0 s}}}{\text{40.0 s - 10.0 s}} \]`

Perform the calculations with the given values from the table. Ensure that the units are consistent, and express the answer with the appropriate unit of rate (e.g., units per second).

`\[ \text{Average Rate} = (X.X - Y.Y)/(40.0 - 10.0) \]`

After obtaining the numerical result, state the final answer in units per second. Provide any relevant context about the significance of the average rate in the given time interval.