Question

Which of the following equations has a degree of 4, x-intercepts located at (-3,0), (7,0) and (-8,0), and a y-intercept located at (0,168)?

1) y = (x + 3)(x - 7)(x + 8)(x - 168)
2) y = (x - 3)(x + 7)(x - 8)(x + 168)
3) y = (x + 3)(x + 7)(x - 8)(x - 168)
4) y = (x - 3)(x - 7)(x + 8)(x + 168)

Answer 1

The equation that satisfies the given conditions has a degree of 4 and x-intercepts at (-3,0), (7,0), and (-8,0), as well as a y-intercept at (0,168).

Step-by-step explanation:

The equation that satisfies the given conditions is:

y = (x + 3)(x - 7)(x + 8)(x - 168)

The equation has a degree of 4 because it contains four terms with variables raised to the power of 1. The x-intercepts are located at (-3,0), (7,0), and (-8,0) because these values make the equation equal to zero for each respective x value. The y-intercept is located at (0,168) because when x is equal to zero, the equation evaluates to 168.