Question

Given v1 = 10 Vpp, vout = -15 Vpp and rf = 7 kΩ, find the values of r1 (in Ω) and the transfer function (in V/V). Write the transfer function in phasor notation.

Answer 1

To find the values of r1 and the transfer function in phasor notation given v1 = 10 Vpp, vout = -15 Vpp, and rf = 7 kΩ, we can use the voltage divider formula Vout = V1 * (rf / (r1 + rf)). Solving for r1 will give its value in Ω.

Step-by-step explanation:

To find the values of r1 and the transfer function in phasor notation given v1 = 10 Vpp, vout = -15 Vpp, and rf = 7 kΩ, we can use the voltage divider formula:

Vout = V1 * (rf / (r1 + rf)).

Substituting the given values into the formula, we get:

-15 = 10 * (7000 / (r1 + 7000)).

Simplifying the equation, we have:

-1.5 + 7 = 0.01r1 + 10.

From here, we can solve for r1 to find its value in Ω.