Final answer:
The sequence of mRNA synthesized from the given DNA template strand is 5'-AUG GCC GGU UAA UUA GCA-3'. The resulting protein sequence is Met-Ala-Gly-Stop-Stop-Ala.
Step-by-step explanation:
The sequence of mRNA synthesized from the given DNA template strand is 5'-AUG GCC GGU UAA UUA GCA-3'. To determine the mRNA sequence, we need to complement the DNA template strand. In RNA, uracil (U) replaces thymine (T). So, A in the DNA template will pair with U in the mRNA sequence. The resulting mRNA sequence will then be translated to determine the sequence of amino acids.
The mRNA sequence 5'-AUG GCC GGU UAA UUA GCA-3' codes for the amino acid sequence Met-Ala-Gly-Stop-Stop-Ala. The N-terminus of the protein corresponds to the methionine (Met) amino acid, while the C-terminus corresponds to the alanine (Ala) amino acid. Therefore, the complete sequence of the translated protein is: Met-Ala-Gly-Stop-Stop-Ala.