Final answer:
To fill a 12.0-gallon gas tank with gasoline that has a density of 0.737 g/ml at 25 °C, you would need 33,468.3624 grams of gasoline.
Step-by-step explanation:
The question involves converting the volume of gasoline a tank can hold into mass, using the density of the gasoline. First, we need to convert the volume from gallons to liters, since the density is given in grams per milliliter, and 1 liter equals 1000 milliliters. One U.S. gallon is equivalent to 3.78541 liters. So, a 12.0-gallon gas tank would hold 12.0 x 3.78541 = 45.42492 liters.
Next, we calculate the mass of gasoline the tank would hold. We use the density of the gasoline, which is 0.737 grams per milliliter, and convert the volume from liters to milliliters by multiplying by 1000. Therefore, the mass of gasoline is calculated as 45.42492 liters x 1000 mL/liter x 0.737 g/mL = 33,468.3624 grams.
So, 33,468.3624 grams of gasoline would fill a 12.0-gallon tank.