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What is the concentration in (a) ppmv, and (b) percent by volume, of carbon monoxide (CO) with a concentration of 103 μg/m3? Assume a temperature of 25°C and pressure of 1 atm.

User Wbdlc
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Final answer:

To calculate the ppmv and percent by volume of CO with a concentration of 103 μg/m³, the molar mass of CO and the molar volume of an ideal gas at 25°C and 1 atm are used to first get the molar concentration, which is then converted to ppmv and percent by volume.

Step-by-step explanation:

The student has asked about the concentration of carbon monoxide (CO) in parts per million by volume (ppmv) and percent by volume when given a concentration of 103 μg/m³. To answer this, we can use the Ideal Gas Law to calculate the molar concentration, which will then be converted to ppmv and percent by volume.

At 25°C and 1 atm, we assume the molar volume of an ideal gas to be 24.45 L/mol. Using the molar mass of CO (28.01 g/mol), a concentration of 103 μg/m³ can be converted to moles per cubic meter, then to ppmv by comparing with the molar volume. To find the percent by volume, we take the ppmv and divide by 10,000 (since 1% is equal to 10,000 ppm).

To calculate this, you first convert 103 μg/m³ to grams per cubic meter by dividing by 1,000,000. Then, divide by the molar mass of CO to get the moles in a cubic meter. Using the molar volume at the given conditions, you can convert moles to volume and then get the ppmv. Finally, divide ppmv by 10,000 to get the percent by volume.

User JoeriShoeby
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