Final answer:
Nitrogen in enalapril is sp² hybridized, with three sp² orbitals forming a bent geometry and one p-orbital contributing to π-bond formation.
Step-by-step explanation:
The hybridization state of nitrogen (N) in enalapril is sp² hybridized. This hybridization implies that nitrogen has three sp² orbitals: two of these orbitals form σ-bonds with adjacent atoms, and the third orbital contains a lone pair of electrons. Additionally, nitrogen has one unhybridized p-orbital which is responsible for forming a π-bond. The geometry of an sp² hybridized nitrogen is bent or angular, with a bond angle close to 120°, however, it may vary slightly depending on the surrounding substituents.