Final answer:
The concentration of potassium alaninate in a 50.0 ml solution with a concentration of 0.193 M remains 0.193 M, as the volume does not change the concentration value.
Step-by-step explanation:
The concentration of potassium alaninate in a 50.0 ml solution with a concentration of 0.193 M is simply the given concentration since the volume does not affect the concentration value but rather indicates the amount of solution we have. The molarity (or molar concentration) represents moles of solute per liter of solution, expressed as moles per liter (M or mol/L). Thus, if you have a 0.193 M potassium alaninate solution, this means you have 0.193 moles of potassium alaninate dissolved in every liter of the solution.
To find out the number of moles present in a 50.0 ml solution, you would use the concentration and the volume:
- 0.193 moles/L * 0.0500 L = 0.00965 moles of potassium alaninate.
This calculation indicates the amount of substance in the given volume, which in this case is 50.0 ml, but does not change the concentration itself. The concentration remains 0.193 M.