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What is the value of x[n] and h[n]?

1) x[n] = 8[n] + 28[n-1] - 8[n-3] and h[n] = 28[n+1] + 28[n-1]
2) x[n] = 8[n] - 28[n-1] + 8[n-3] and h[n] = 28[n+1] - 28[n-1]
3) x[n] = 8[n] + 28[n-1] - 8[n-3] and h[n] = 28[n+1] - 28[n-1]
4) x[n] = 8[n] - 28[n-1] - 8[n-3] and h[n] = 28[n+1] + 28[n-1]

User Rathma
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1 Answer

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Final answer:

The value of x[n] is 8[n] + 28[n-1] - 8[n-3] and the value of h[n] is 28[n+1] - 28[n-1].

Step-by-step explanation:

The correct option is 3) x[n] = 8[n] + 28[n-1] - 8[n-3] and h[n] = 28[n+1] - 28[n-1].

In this option, x[n] represents a sequence that adds together the values of n, n-1, and n-3 with different coefficients. h[n] represents a sequence that subtracts the values of n+1 and n-1 with matching coefficients. This option aligns with the expressions provided for x[n] and h[n] in the question.

User Michael Coxon
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