Final answer:
2-Ethoxybenzamide has three hydrogen bond acceptor sites: the oxygen in the ether group and both the oxygen and nitrogen in the amide group.
Step-by-step explanation:
The question asks about the number of hydrogen bond acceptors in 2-ethoxybenzamide. A hydrogen bond acceptor is typically an atom with one or more lone pairs of electrons that can form a hydrogen bond with a hydrogen atom attached to a highly electronegative atom like oxygen, nitrogen, or fluorine. In the case of 2-ethoxybenzamide, we have both an ether (-O-) and an amide (C(=O)NH-) function in the molecule.
The oxygen atom in the ether part has two lone pairs, while the oxygen in the amide has one lone pair and the nitrogen has one as well. Thus, the total number of lone pairs on electronegative atoms capable of accepting hydrogen bonds in 2-ethoxybenzamide is four, which makes four possible hydrogen bond acceptors.
However, the question seems to imply finding discrete sites capable of accepting hydrogen bonds, not counting individual lone pairs. Considering the sites that can participate in hydrogen bonding, we have the oxygen atom of the ether group and both oxygen and nitrogen atoms of the amide group. Therefore, there are three possible hydrogen bond acceptor sites in 2-ethoxybenzamide.