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Let a = and b = . Compute the following:

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Final answer:

The student needs help with the quadratic formula. The equation given has coefficients a=1.00, b=10.0, and c=-200. Substituting these values and simplifying gives solutions x=10 and x=-20.

Step-by-step explanation:

The student appears to be asking for help with solving a quadratic equation using the quadratic formula, which is x = (-b ± √(b² - 4ac))/(2a). The values of a, b, and c were provided in the question. For this scenario, the constants are a = 1.00, b = 10.0, and c = -200. We can substitute these values directly into the quadratic formula to find the solutions for x.

Substituting the values we get, x = (-10.0 ± √((10.0)² - 4(1.00)(-200)))/(2(1.00)). Solving further, x = (-10.0 ± √(100 + 800))/2, which simplifies to x = (-10.0 ± √900)/2. Finally, we find the two solutions x = (-10.0 + 30)/2 and x = (-10.0 - 30)/2, which are x = 10 and x = -20 respectively.

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