Final answer:
The equilibrium constant (Keq) for the reaction 2 H₂(g) + O₂(g) → 2 H₂O(g) cannot be directly calculated as the concentrations at equilibrium are not given. However, based on the given information, the equilibrium constant for the reverse reaction is very small, and the approximate value of Keq for the forward reaction can be determined.
Step-by-step explanation:
The equilibrium constant (Keq) for the reaction 2 H₂(g) + O₂(g) → 2 H₂O(g) can be calculated using the concentrations at equilibrium. However, the information provided does not include the concentrations of the reactants and products at equilibrium, so we cannot directly calculate the value of Keq.
According to the given information, the equilibrium constant (Ke) for the reverse reaction, the decomposition of water to form O₂ and H₂, is very small: Ke = 1/(2.4 × 10¹⁷) ≈ 4.2 × 10¯⁴⁸. The value of Keq for the forward reaction can be approximated to be the reciprocal of Ke: Keq ≈ 1/Ke ≈ 2.4 × 10¹⁷.