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If g(1)=-1 and g(5)=-6, what is the value of the integral?

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Final Answer:

The integral's value is -21, representing the signed area under a curve. This result implies that the net accumulation of the function's values over the specified interval is negative 21 units.

Step-by-step explanation:

Let's find the antiderivative of g(x) using the given values of g(1) and g(5). We can use the definition of an antiderivative as follows:

An antiderivative of a function f(x) is a differentiable function F(x) such that F'(x) = f(x).

Since we know the values of g(1) and g(5), we can find an antiderivative F(x) such that F'(x) = g(x). Let's call this function F(x).

Now, we can find F(x) by integrating g(x) using the given values. We have:

F(x) = -1 * x + C, where C is a constant of integration.

We know that F(1) = -1, which gives us:

-1 = -1 * 1 + C. Therefore, C = 0.

Similarly, we know that F(5) = -6, which gives us:

-6 = -1 * 5 + 0. Therefore, F(x) = -x - 6.

So, the value of the integral from 1 to 5 is:

∫^5_1 g(x) dx = F(5) - F(1) = (-6 - 1) - (-1 - 0) = -21.

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