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How many grams of NaCl are contained in 350 ml of a 0.250 M solution of sodium chloride?

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Final answer:

To calculate the mass of NaCl in 350 ml of a 0.250 M NaCl solution, convert the volume to liters, calculate the moles of NaCl using the molarity, and then convert moles to grams using the molar mass of NaCl. The result is 5.114 grams of NaCl.

Step-by-step explanation:

Calculating the Mass of NaCl in a Solution

To determine how many grams of NaCl are contained in 350 ml of a 0.250 M solution, we first need to find the number of moles of NaCl in this volume. The molarity (M) of a solution is defined as moles of solute per liter of solution. Therefore, we can use the formula:

Moles of NaCl = Molarity (M) × Volume (L)

For this problem:

Convert 350 ml to liters by dividing by 1000: 350 ml / 1000 = 0.350 L.

Calculate the moles of NaCl: 0.250 M × 0.350 L = 0.0875 moles.

Now, we need to convert moles to grams. The molar mass of NaCl is 58.44 g/mol.

Grams of NaCl = Moles of NaCl × Molar mass of NaCl = 0.0875 moles × 58.44 g/mol.

Therefore, we have: 0.0875 × 58.44 = 5.114 grams of NaCl.

There are 5.114 grams of NaCl in 350 ml of a 0.250 M solution of sodium chloride.

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